1. What is Inductor Impedance?

The impedance (Z) of an inductor represents its opposition to alternating current (AC). It consists of purely reactive (imaginary) component with no real (resistive) part, hence the 'j' notation.

2. How Does the Calculator Work?

The calculator uses the inductor impedance formula:

Where:

• \( Z \) — Impedance (ohms, Ω)
• \( j \) — Imaginary unit (√-1)
• \( f \) — Frequency (hertz, Hz)
• \( L \) — Inductance (henries, H)
• \( \pi \) — Pi (approximately 3.1416)

Explanation: The impedance increases with both frequency and inductance. At DC (f=0), the impedance is zero (ideal inductor acts as short circuit).

3. Importance of Impedance Calculation

Details: Calculating inductor impedance is essential for designing AC circuits, filters, and resonant circuits. It helps determine voltage-current phase relationships and power dissipation.

4. Using the Calculator

Tips: Enter frequency in Hz and inductance in H. Both values must be positive numbers. The result is the complex impedance in ohms (Ω).

5. Frequently Asked Questions (FAQ)

Q1: What does the 'j' represent?
A: The 'j' represents the imaginary unit (√-1), indicating the 90° phase shift between voltage and current in an inductor.

Q2: How does impedance change with frequency?
A: Impedance is directly proportional to frequency - doubling the frequency doubles the impedance.

Q3: What is the phase relationship in an inductor?
A: Current lags voltage by 90° in a pure inductor.

Q4: Does this apply to real inductors?
A: Real inductors also have some resistance (winding resistance), so their impedance has both real and imaginary components.

Q5: What about capacitor impedance?
A: Capacitor impedance is Z = 1/(jωC) = -j/(ωC), where ω = 2πf. Current leads voltage by 90° in a capacitor.